Câu hỏi
Cho sơ đồ sau: \(etilen\xrightarrow{{ + {H_2}O/xt}}\,X\,\xrightarrow{{xt,{t^0}}}Y\xrightarrow{{xt\,Na\,,{t^0}}}\,po\lim e\,M.\) Vậy M là:
- A polietilen.
- B polibutađien.
- C poli ( vinyl clorua).
- D poliisopren.
Lời giải chi tiết:
\(\begin{gathered}
etilen(C{H_2} = C{H_2})\xrightarrow{{ + {H_2}O/xt}}\,C{H_3}C{H_2}OH(X)\xrightarrow{{xt,{t^0}}}C{H_2} = CH - CH = C{H_2}(Y) \hfill \\
\xrightarrow{{xt\,Na\,,{t^0}}}\,( - C{H_2} - CH = CH - C{H_2} - )po\lim e\,M. \hfill \\
C{H_2} = C{H_2} + {H_2}O\xrightarrow{{{H^ + },{t^0}}}C{H_3}C{H_2}OH \hfill \\
2C{H_3}C{H_2}OH\xrightarrow{{A{l_2}{O_3},C{r_2}{O_3},{{450}^0}C}}C{H_2} = CH - CH = C{H_2} + 2{H_2}O + {H_2} \hfill \\
nC{H_2} = CH - CH = C{H_2}\xrightarrow[{Na}]{{xt,{t^0},p}}\underbrace {{{( - C{H_2} - CH = CH - C{H_2} - )}_n}}_{poli\,butadien} \hfill \\
\end{gathered} \)
Đáp án B
Câu hỏi trước
