Câu hỏi
\(\sqrt {\frac{9}{{16}}.{x^2}.{y^6}} \)
- A \(\frac{3}{4}.x.y^3\)
- B \(\frac{3}{4}.\left| x \right|.y^3\)
- C \(\frac{3}{4}.\left| x \right|.\left| {{y^3}} \right|\)
- D \(\frac{3}{4}.x.\left| {{y^3}} \right|\)
Lời giải chi tiết:
\(\sqrt {\frac{9}{{16}}.{x^2}.{y^6}} = \sqrt {\frac{9}{{16}}} .\sqrt {{x^2}} .\sqrt {{y^6}} = \frac{3}{4}.\left| x \right|.\left| {{y^3}} \right|\)