Tìm \(x\), biết:

a) \(\left( {x - \frac{3}{5}} \right):\frac{{ - 1}}{3} = 0,4\)

b) \(\left| {x - 1} \right| = 4\)

a) \(\left( {x - \frac{3}{5}} \right):\frac{{ - 1}}{3} = 0,4\)

\(\left( {x - \frac{3}{5}} \right) = \frac{2}{5}.\frac{{ - 1}}{3}\)

\(x - \frac{3}{5} = \frac{{ - 2}}{{15}}\)

\(x = \frac{{ - 2}}{{15}} + \frac{3}{5}\)

\(x = \frac{7}{{15}}\)

Vậy \(x = \frac{7}{{15}}\).

b) \(\left| {x - 1} \right| = 4\)

\( \Rightarrow x - 1 = 4\) hoặc \(x - 1 =  - 4\)

\( \Rightarrow x = 5\) hoặc \(x =  - 3\)

Vậy \(x = 5\) hoặc \(x =  - 3\)