Tìm \(x\) biết:
a) \(7 + 2\left( {x - 3} \right) = 11\)
b) \({\left( {x + 2} \right)^3} + {4.3^2} = 63\)
Giải bài toán ngược để tìm \(x\)
a) \(7 + 2\left( {x - 3} \right) = 11\)
\(\begin{array}{l}2\left( {x - 3} \right) = 11 - 7\\2\left( {x - 3} \right) = 4\\x - 3 = 4:2\\x - 3 = 2\\x = 2 + 3\\x = 5\end{array}\)
Vậy \(x = 5\).
b) \({\left( {x + 2} \right)^3} + {4.3^2} = 63\)
\(\begin{array}{l}{\left( {x + 2} \right)^3} + 4.9 = 63\\{\left( {x + 2} \right)^3} + 36 = 63\\{\left( {x + 2} \right)^3} = 63 - 36\\{\left( {x + 2} \right)^3} = 27\\{\left( {x + 2} \right)^3} = {3^3}\\x + 2 = 3\\x = 3 - 2\\x = 1\end{array}\)
Vậy \(x = 1\).