Thu gọn đa thức 4x2y+6x3y2−10x2y+4x3y24{x^2}y + 6{x^3}{y^2} - 10{x^2}y + 4{x^3}{y^2}4x2y+6x3y2−10x2y+4x3y2 ta được
Ta có:
4x2y+6x3y2−10x2y+4x3y2=(4x2y−10x2y)+(6x3y2+4x3y2)=−6x2y+10x3y24x2y+6x3y2−10x2y+4x3y2=(4x2y−10x2y)+(6x3y2+4x3y2)=−6x2y+10x3y2\begin{array}{l}4{x^2}y + 6{x^3}{y^2} - 10{x^2}y + 4{x^3}{y^2}\\ = \left( {4{x^2}y - 10{x^2}y} \right) + \left( {6{x^3}{y^2} + 4{x^3}{y^2}} \right)\\ = - 6{x^2}y + 10{x^3}{y^2}\end{array}4x2y+6x3y2−10x2y+4x3y2=(4x2y−10x2y)+(6x3y2+4x3y2)=−6x2y+10x3y24x2y+6x3y2−10x2y+4x3y2=(4x2y−10x2y)+(6x3y2+4x3y2)=−6x2y+10x3y2
