lim(1n+2)\lim\left( {\dfrac{1}{n} + 2} \right)lim(n1+2) bằng
1.
0.
2.
+∞+ \infty+∞.
Ta có lim(1n+2)=lim1n+lim2=0+2=2\lim\left( {\dfrac{1}{n} + 2} \right) = \lim\dfrac{1}{n} + \lim 2 = 0 + 2 = 2lim(n1+2)=limn1+lim2=0+2=2.
