Tìm F(x)=∫π2dxF(x) = \int {{\pi ^2}dx}F(x)=∫π2dx.
F(x)=π2x+CF(x) = {\pi ^2}x + CF(x)=π2x+C
F(x)=π2x22+CF(x) = \frac{{{\pi ^2}{x^2}}}{2} + CF(x)=2π2x2+C
F(x)=2πx+CF(x) = 2\pi x + CF(x)=2πx+C
F(x)=π33F(x) = \frac{{{\pi ^3}}}{3}F(x)=3π3
F(x)=∫π2dx=π2∫dx=π2x+CF(x) = \int {{\pi ^2}dx} = {\pi ^2}\int {dx} = {\pi ^2}x + CF(x)=∫π2dx=π2∫dx=π2x+C.
