Đề thi giữa học kì 2 Toán 11 - Đề số 1

${a^{\frac{5}{2}}}$

$a$

${a^{\frac{3}{2}}}$

${a^{\frac{1}{4}}}$

$\frac{5}{{2a}}$

$\frac{{5a}}{2}$

$\frac{2}{{5a}}$

$\frac{{2a}}{5}$

$y = {\left( {\frac{1}{e}} \right)^x}$

$y = {\left( {\sqrt {\frac{1}{\pi }} } \right)^x}$

$y = {\left( {\frac{1}{3}} \right)^x}$

$y = {\left( {\sqrt[{2024}]{\pi }} \right)^x}$

$S = \left( { - \infty ;1} \right)$

$S = \left( { - \infty ;2} \right)$

$S = \left( {2; + \infty } \right)$

$S = \left( {1; + \infty } \right)$

$D = \left( { - \infty ; - 1} \right] \cup \left[ {3; + \infty } \right)$

$D = \left[ { - 1;3} \right]$

$D = \left( { - \infty ; - 1} \right) \cup \left( {3; + \infty } \right)$

$D = \left( { - 1;3} \right)$

$P = {x^{\frac{4}{3}}}$

$P = {x^{\frac{5}{3}}}$

$P = {x^{\frac{7}{3}}}$

$P = {x^{\frac{8}{3}}}$

$y = {\log _{\frac{1}{2}}}x$

$y = {\log _2}x$

$y = {2^x}$

$y = {\left( {\frac{1}{2}} \right)^x}$